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which polyhedron has more faces than an octahedron but fewer faces than an icosahedron?
a. dodecahedron
b. hexahedron
c. tetrahedron
d. cube
Identify the face counts of the given reference polyhedra
An octahedron has 8 faces, and an icosahedron has 20 faces. We need to find a polyhedron with a face count \(F\) such that:
$$8 < F < 20$$
Determine the face counts of the options
- A. Dodecahedron: 12 faces
- B. Hexahedron: 6 faces
- C. Tetrahedron: 4 faces
- D. Cube: 6 faces
Select the option that satisfies the inequality
The dodecahedron has 12 faces, which satisfies \(8 < 12 < 20\).
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- A. Dodecahedron (Correct answer)
- B. Hexahedron
- C. Tetrahedron
- D. Cube