Question

question 3 of 10
select the two binomials that are factors of this trinomial.
$x^2 + 3x - 28$
a. $x + 4$
b. $x - 4$
c. $x + 7$
d. $x - 7$

Explanation:

Step1: Recall factoring trinomials

To factor \(x^2 + 3x - 28\), we need two numbers that multiply to \(-28\) and add to \(3\).

Step2: Find the numbers

The numbers are \(7\) and \(-4\) because \(7\times(-4)=-28\) and \(7 + (-4)=3\).

Step3: Write the factors

So, \(x^2 + 3x - 28=(x + 7)(x - 4)\).

Answer:

B. \(x - 4\), C. \(x + 7\)