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question #10
reference q.47386
i want to accelerate a car from 100 km/hr uniformly at 1.3m/s² for 1.31 s. how far does the car move in that time?
Step1: Convert initial velocity to m/s
First, convert 100 km/hr to m/s. $100\times\frac{1000}{3600}\approx27.78$ m/s.
Step2: Use the kinematic - equation
The kinematic equation for displacement $s = v_0t+\frac{1}{2}at^{2}$, where $v_0$ is the initial velocity, $t$ is the time, and $a$ is the acceleration.
Substitute $v_0 = 27.78$ m/s, $a = 1.3$ m/s², and $t = 1.31$ s into the equation.
$$
LATEXBLOCK0
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