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Question
question 5 of 10
the heights of 200 adults were recorded and divided into two categories.
which two-way frequency table correctly shows the marginal frequencies?
a.
b.
c.
d.
Identify given values
We are given the heights of 200 adults divided into categories:
- Total adults: \(200\)
- Males \(6'\) or over: \(12\)
- Males under \(6'\): \(86\)
- Females \(6'\) or over: \(3\)
Calculate missing values
Let \(x\) be the number of females under \(6'\).
The sum of all four joint frequencies must equal the total of 200 adults:
Calculate marginal frequencies
Now we calculate the row and column totals (marginal frequencies):
- Total Males: \(12 + 86 = 98\)
- Total Females: \(3 + 99 = 102\)
- Total \(6'\) or over: \(12 + 3 = 15\)
- Total Under \(6'\): \(86 + 99 = 185\)
- Grand Total: \(98 + 102 = 200\) (or \(15 + 185 = 200\))
Match with options
Let's check the options for the correct values:
- Option A: Total is 298 (Incorrect).
- Option B: Total is 215 (Incorrect).
- Option C:
- Male row: \(12\) (\(6'\) or over), \(86\) (Under \(6'\)), Total = \(100\) (Incorrect, \(12 + 86 = 98\)).
- Option D (partially cut off but let's reconstruct the values):
- Male row: \(12\), \(86\), Total = \(98\).
- Female row: \(3\), \(99\), Total = \(102\).
- Total row: \(15\), \(185\), Total = \(200\).
Let's double check the visible parts of Option D:
- Male row: \(12\), \(86\), Total = \(98\).
This matches our calculated values. Thus, Option D is the correct table.
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- (A) Table with grand total 298
- (B) Table with grand total 215
- (C) Table with incorrect male total of 100
- (D) Table with correct marginal frequencies (grand total 200, male total 98, female total 102) (Correct answer)