Question

question 10 of 29
group the following electronic configurations of neutral elements in pairs according to those you would expect to show similar chemical properties.
set a
set b
answer bank
$1s^2 2s^2 2p^3$
$1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6$
$1s^2 2s^2 2p^6 3s^2 3p^3$
$1s^2 2s^2 2p^6 3s^2 3p^6$

Explanation:

Step1: Recall Chemical Property Rule

Elements with same valence electron configuration (same group) have similar chemical properties. Valence electrons are in outermost shell.

Step2: Analyze Each Configuration

• \(1s^2 2s^2 2p^3\): Valence electrons \(2s^2 2p^3\) (n=2).
• \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6\): Valence electrons \(4s^2 4p^6\) (noble gas, n=4).
• \(1s^2 2s^2 2p^6 3s^2 3p^3\): Valence electrons \(3s^2 3p^3\) (n=3, same as \(2s^2 2p^3\) in terms of \(s^2 p^3\) configuration).
• \(1s^2 2s^2 2p^6 3s^2 3p^6\): Valence electrons \(3s^2 3p^6\) (noble gas, n=3, same as \(4s^2 4p^6\) in terms of \(s^2 p^6\) configuration).

Step3: Group by Valence Config

• Pair 1: \(1s^2 2s^2 2p^3\) (n=2, \(s^2 p^3\)) and \(1s^2 2s^2 2p^6 3s^2 3p^3\) (n=3, \(s^2 p^3\)) → similar (Group 15).
• Pair 2: \(1s^2 2s^2 2p^6 3s^2 3p^6\) (n=3, noble gas) and \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6\) (n=4, noble gas) → similar (noble gases).

Answer:

Set A: \(1s^2 2s^2 2p^3\), \(1s^2 2s^2 2p^6 3s^2 3p^3\)
Set B: \(1s^2 2s^2 2p^6 3s^2 3p^6\), \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6\)