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Question
a quarterback back pedals 2.2 meters southward and then runs 6.8 meters northward. for this motion, what is the distance moved? distance (m) = what is the magnitude and direction of the displacement? magnitude (m) = dirn =
Step1: Calculate the distance
Distance is the total path length. We add the magnitudes of each part of the motion.
$2.2 + 6.8$
Step2: Calculate the displacement magnitude
Displacement is the straight - line distance from the starting point to the ending point. We take the northward direction as positive and southward as negative. So displacement $d=6.8 - 2.2$.
Step3: Determine the displacement direction
Since the result of the displacement calculation is positive, the direction is northward.
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Distance (m) = $9$
Magnitude (m) = $4.6$
Dir'n = North