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a quarterback back pedals 2.2 meters southward and then runs 6.8 meters…

Question

a quarterback back pedals 2.2 meters southward and then runs 6.8 meters northward. for this motion, what is the distance moved? distance (m) = what is the magnitude and direction of the displacement? magnitude (m) = dirn =

Explanation:

Step1: Calculate the distance

Distance is the total path length. We add the magnitudes of each part of the motion.
$2.2 + 6.8$

Step2: Calculate the displacement magnitude

Displacement is the straight - line distance from the starting point to the ending point. We take the northward direction as positive and southward as negative. So displacement $d=6.8 - 2.2$.

Step3: Determine the displacement direction

Since the result of the displacement calculation is positive, the direction is northward.

Answer:

Distance (m) = $9$
Magnitude (m) = $4.6$
Dir'n = North