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Question
- quadrilateral pqrs is a rectangle, qt = 10b + 23, and rt = 15b - 12. what is st?
Step1: Use the property of rectangle diagonals
In a rectangle, the diagonals are equal and bisect each other. So \(QT = RT\).
$$10b + 23=15b - 12$$
Step2: Solve for \(b\)
Subtract \(10b\) from both sides:
$$23 = 5b-12$$
Add \(12\) to both sides:
$$35 = 5b$$
Divide both sides by \(5\):
$$b = 7$$
Step3: Find \(QT\)
Substitute \(b = 7\) into \(QT=10b + 23\):
$$QT=10\times7 + 23=70 + 23=93$$
Step4: Use the property of diagonal bisection
Since \(ST = QT\) (diagonals bisect each other in a rectangle)
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