QUESTION IMAGE
Question
prove the identity.
\\\cot x \left(1 + \tan^2 x\
ight) = \frac{1}{\sin x \cos x}\\
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statement | reason
--- | ---
\\(\cot x \left(1 + \tan^2 x\
ight)\\) |
\\(=\\) | select
Apply Pythagorean identity
Using the Pythagorean Identities knowledge point
$$
1 + \tan^2 x = \sec^2 x
$$
$$
\cot x (1 + \tan^2 x) = \cot x \sec^2 x
$$
Convert to sine and cosine
Using the Quotient Identities and Reciprocal Identities knowledge points
$$
\cot x = \frac{\cos x}{\sin x}, \quad \sec^2 x = \frac{1}{\cos^2 x}
$$
$$
\cot x \sec^2 x = \frac{\cos x}{\sin x} \cdot \frac{1}{\cos^2 x}
$$
Simplify the expression
Using the Trigonometric Identities knowledge point
$$
\frac{\cos x}{\sin x \cdot \cos^2 x} = \frac{1}{\sin x \cos x}
$$
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To prove the identity \(\cot x (1 + \tan^2 x) = \frac{1}{\sin x \cos x}\), the first step in the proof table is:
- Statement: \(\cot x \sec^2 x\)
- Reason: Pythagorean Identity