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a programmer is writing a loop that increments an index by 2 each time …

Question

a programmer is writing a loop that increments an index by 2 each time it runs. the loop starts with the index at 1 on the first iteration. on the fourth iteration, the programmers loop index will be at

Explanation:

Step1: Determine the formula for the index value

The index starts at \(1\) and is incremented by \(2\) each iteration. The formula for the index \(i\) after \(n\) iterations is \(i = 1+(n - 1)\times2\).

Step2: Substitute \(n = 4\) into the formula

When \(n = 4\), we have \(i=1+(4 - 1)\times2\). First, calculate \((4 - 1)=3\). Then, \(3\times2 = 6\). Finally, \(1+6=7\).

Answer:

\(7\)