Question

a professor had students keep track of their social interactions for a week. the number of social interactions over the week is shown in the frequency table below. using the table answer the following. a. how many students participated in the study? b. what is the class width? c. what class has the highest frequency?

Explanation:

Step1: Calculate total number of students

To find the number of students who participated in the study, sum up all the frequencies.
$$14 + 16+11 + 20+16+12+4+6+0+4$$
$$=(14 + 16)+(11 + 20)+(16 + 12)+(4 + 6)+(0 + 4)$$
$$=30+31+28+10+4$$
$$=103$$

Step2: Calculate class width

The class width is the difference between the upper - limit and lower - limit of a class. For example, for the class \(25 - 29\), the class width is \(29−25 = 4\)

Step3: Identify class with highest frequency

Compare the frequencies: \(14,16,11,20,16,12,4,6,0,4\). The highest frequency is \(20\), and the corresponding class is \(40 - 44\)

Answer:

A. \(103\)
B. \(4\)
C. \(40 - 44\)