Question

problem 5: a bowling ball with a mass of 2.85 kg is going at a speed of 4 m/s. its moment arm to some observer is 5 m. find the angular momentum of the ball. neglect any internal motion of the ball.

Explanation:

Step1: Recall the formula for angular momentum

The formula for angular momentum \(L\) of a point - like object is \(L = mvr\), where \(m\) is the mass, \(v\) is the linear velocity, and \(r\) is the moment arm.

Step2: Substitute the given values into the formula

Given \(m = 2.85\space kg\), \(v=4\space m/s\), and \(r = 5\space m\).
Substitute these values into \(L=mvr\):
\(L=(2.85\space kg)\times(4\space m/s)\times(5\space m)\)
First, calculate \(4\times5 = 20\), then \(L=2.85\times20\space kg\cdot m^{2}/s\)
\(L = 57\space kg\cdot m^{2}/s\)

Answer:

\(57\space kg\cdot m^{2}/s\)