Question

predict what will be observed in each experiment below.
a student sees tiny bubbles clinging to the inside of an unopened plastic bottle full of carbonated soft drink. the student squeezes the bottle.
a student has two unopened 33 cl cans containing carbonated water. can a has been stored in the garage (32°c) and can b has been stored in the fridge (8°c). the student opens one can at the time, both cans make a fizz.

Explanation:

• First experiment: When the student squeezes the bottle, the pressure inside the bottle increases. According to Henry's Law (\(C = kP\), where \(C\) is the concentration of the gas in the liquid, \(k\) is the Henry's Law constant, and \(P\) is the partial pressure of the gas above the liquid), an increase in pressure leads to an increase in the solubility of the gas (\(CO_2\)) in the soft - drink. So, the bubbles (which are \(CO_2\) gas) will shrink as more \(CO_2\) dissolves back into the liquid, and some may vanish.
• Second experiment: The solubility of a gas in a liquid decreases with an increase in temperature. Can A is at a higher temperature (\(32^{\circ}C\)) than Can B (\(8^{\circ}C\)). At higher temperatures, the \(CO_2\) gas in Can A is less soluble. When the can is opened, the excess \(CO_2\) will escape more vigorously. So, Can A will make a louder and stronger fizz than Can B.

Answer:

• First experiment: The bubbles will shrink, and some may vanish.
• Second experiment: Can A will make a louder and stronger fizz than Can B.