Question

predict the products of the following reaction. if no reaction will occur, use the no reaction button.
be sure your chemical equation is balanced!
$\ce{ch_{3}cch(g) + o_{2}(g) -> \square}$

Explanation:

Step1: Determine the type of reaction

This is a combustion reaction. In a combustion reaction of a hydrocarbon (here \(CH_3CCH\) is a hydrocarbon, its formula can be written as \(C_3H_4\)), the products are \(CO_2\) and \(H_2O\) when there is sufficient oxygen.

Step2: Write the un - balanced equation

\(C_3H_4(g)+O_2(g)\to CO_2(g) + H_2O(g)\)

Step3: Balance the carbon atoms

There are 3 carbon atoms in \(C_3H_4\). So, we put a coefficient of 3 in front of \(CO_2\):
\(C_3H_4(g)+O_2(g)\to 3CO_2(g)+H_2O(g)\)

Step4: Balance the hydrogen atoms

There are 4 hydrogen atoms in \(C_3H_4\). So, we put a coefficient of 2 in front of \(H_2O\):
\(C_3H_4(g)+O_2(g)\to 3CO_2(g)+2H_2O(g)\)

Step5: Balance the oxygen atoms

On the right - hand side, the total number of oxygen atoms is \(3\times2 + 2\times1=8\). So, we put a coefficient of 4 in front of \(O_2\) on the left - hand side.

The balanced chemical equation is:
\(C_3H_4(g)+4O_2(g)\to 3CO_2(g)+2H_2O(g)\)

Answer:

\(C_3H_4(g)+4O_2(g)\to 3CO_2(g)+2H_2O(g)\)