QUESTION IMAGE
Question
practice using asa and aas congruence theorems.
what additional information could be used to prove that
δxyz ≅ δfeg using asa or aas? check all that apply.
□ ∠z ≅ ∠g and xz ≅ fg
□ ∠z ≅ ∠g and ∠y ≅ ∠e
□ xz ≅ fg and zy ≅ ge
□ xy ≅ ef and zy ≅ fg
□ ∠z ≅ ∠g and xy ≅ fe
Step1: Recall ASA and AAS
ASA (Angle - Side - Angle) requires two angles and the included side to be congruent. AAS (Angle - Angle - Side) requires two angles and a non - included side to be congruent.
Step2: Analyze Option 1 ($\angle Z\cong\angle G$ and $\overline{XZ}\cong\overline{FG}$)
We already know (from the diagram, likely) that $\angle X\cong\angle F$ (the marked angles). If we have $\angle Z\cong\angle G$ and $\overline{XZ}\cong\overline{FG}$, then we have AAS (two angles $\angle X\cong\angle F$, $\angle Z\cong\angle G$ and the non - included side $\overline{XZ}\cong\overline{FG}$) or ASA? Wait, let's check the triangles. $\triangle XYZ$ and $\triangle FEG$. $\angle X$ and $\angle F$ are corresponding, $\angle Z$ and $\angle G$ are corresponding, and side $XZ$ and $FG$ are corresponding. So with $\angle X\cong\angle F$, $\angle Z\cong\angle G$, and $XZ\cong FG$, by AAS, the triangles are congruent. So this option works.
Step3: Analyze Option 2 ($\angle Z\cong\angle G$ and $\angle Y\cong\angle E$)
If we have three angles congruent ($\angle X\cong\angle F$, $\angle Y\cong\angle E$, $\angle Z\cong\angle G$), AAA (Angle - Angle - Angle) does not prove congruence, it proves similarity. So this option does not work for proving congruence using ASA or AAS.
Step4: Analyze Option 3 ($\overline{XZ}\cong\overline{FG}$ and $\overline{ZY}\cong\overline{GE}$)
This is S - S (Side - Side) with an unknown angle. This is not ASA or AAS. So this option does not work.
Step5: Analyze Option 4 ($\overline{XY}\cong\overline{EF}$ and $\overline{ZY}\cong\overline{FG}$)
These are two sides that are not related by the angle congruence rules of ASA or AAS. This is not a valid ASA or AAS combination. So this option does not work.
Step6: Analyze Option 5 ($\angle Z\cong\angle G$ and $\overline{XY}\cong\overline{FE}$)
We know $\angle X\cong\angle F$. If $\angle Z\cong\angle G$ and $\overline{XY}\cong\overline{FE}$, let's see. $\angle X\cong\angle F$, $\angle Z\cong\angle G$, and $\overline{XY}\cong\overline{FE}$. Let's check the sides. $\overline{XY}$ is a side in $\triangle XYZ$, $\overline{FE}$ is a side in $\triangle FEG$. The angles: $\angle X$ is between $\overline{XZ}$ and $\overline{XY}$, $\angle F$ is between $\overline{FG}$ and $\overline{FE}$. If $\angle X\cong\angle F$, $\angle Z\cong\angle G$, and $\overline{XY}\cong\overline{FE}$, then we can use AAS. Wait, let's re - check. Wait, maybe I made a mistake earlier. Wait, the first option: $\angle Z\cong\angle G$, $\overline{XZ}\cong\overline{FG}$, and $\angle X\cong\angle F$ (the marked angle). For the fifth option: $\angle Z\cong\angle G$, $\overline{XY}\cong\overline{FE}$, and $\angle X\cong\angle F$. Let's see the correspondence. In $\triangle XYZ$: angles are $\angle X$, $\angle Y$, $\angle Z$. In $\triangle FEG$: angles are $\angle F$, $\angle E$, $\angle G$. If $\angle X\cong\angle F$, $\angle Z\cong\angle G$, and $\overline{XY}\cong\overline{FE}$, then the side $\overline{XY}$ is opposite $\angle Z$ in $\triangle XYZ$, and $\overline{FE}$ is opposite $\angle G$ in $\triangle FEG$. Since $\angle Z\cong\angle G$ and $\angle X\cong\angle F$, by AAS (two angles and a non - included side), this would work? Wait, no, let's go back to the first option. Wait, the first option: $\overline{XZ}$ is between $\angle X$ and $\angle Z$, so if $\angle X\cong\angle F$, $\angle Z\cong\angle G$, and $\overline{XZ}\cong\overline{FG}$, that's ASA? Wait, $\angle X$ is between $\overline{XZ}$ and $\overline{XY}$, $\angle F$ is between $\overline{FG}$ and $\overline{FE}$. So $\overline{XZ}…
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
$\boldsymbol{\angle Z\cong\angle G}$ and $\boldsymbol{\overline{XZ}\cong\overline{FG}}$ (the first option)