Question

7.5.1 practice 2
type your answers in the boxes below.

1. the temperature at 2 p.m. is 12 degrees celsius above 0. what is the temperature?

12 degrees c

1. the temperature at 10 p.m. is 6 degrees celsius below 0. what is the temperature?

degrees c

1. what is the change in temperature from 2 p.m. and 10 p.m.? degrees c

Explanation:

Step1: Solve Question 2

Temperatures below 0 are represented by negative numbers. So 6 degrees below 0 is $-6$ degrees C.

Step2: Solve Question 3

The temperature at 2 p.m. is $12^\circ$C, at 10 p.m. is $-6^\circ$C. The change is $-6 - 12 = -18$? Wait, no, change in temperature is final - initial. So $-6 - 12 = -18$? Wait, no, the absolute change? Wait, the problem says "change in temperature". So from 12 to -6, the difference is $-6 - 12 = -18$, but the magnitude of change is 18? Wait, no, let's check: initial is 12, final is -6. So change is final - initial = $-6 - 12 = -18$. But maybe the question is asking for the absolute value? Wait, no, the problem says "change in temperature". So the answer is -18? Wait, but let's re-examine.

Wait, question 2: temperature at 10 p.m. is 6 degrees below 0, so that's $-6$ degrees C.

Question 3: change in temperature from 2 p.m. (12) to 10 p.m. (-6). So change is $-6 - 12 = -18$. So the change is -18 degrees C (meaning a decrease of 18 degrees).

But let's do step by step:

Question 2:

Temperature below 0 is negative. So 6 below 0 is $-6$.

Question 3:

Initial temp (2 p.m.): $12^\circ$C.

Final temp (10 p.m.): $-6^\circ$C.

Change in temperature = Final - Initial = $-6 - 12 = -18$.

Answer:

1. -6
2. -18