Question

practice multiplying fractions by whole numbers
keona and andre have packages of clay for an art project. keona has 4 packages of clay, and each package weighs \\(\frac{5}{2}\\) kilograms. andre has 8 packages of clay, and each package weighs \\(\frac{6}{5}\\) kilograms.
which statements about the weight of the packages are true?
select all the correct answers.
a keona’s packages of clay weigh \\(\frac{9}{2}\\) kilograms in all.
b andre’s packages of clay weigh \\(9\frac{3}{5}\\) kilograms in all.
c andre’s packages of clay weigh 2 times more than keona’s because 8 is 2 times more than 4.
d andre’s packages of clay weigh more than keona’s packages of clay because 8 packages is more than 4 packages.
e keona’s packages of clay weigh more than andre’s packages of clay because 10 kilograms is greater than \\(9\frac{3}{5}\\) kilograms.

Explanation:

Step1: Calculate Keona's total weight

Keona has 4 packages, each \(\frac{5}{2}\) kg. Total weight: \(4\times\frac{5}{2} = 10\) kg.

Step2: Calculate Andre's total weight

Andre has 8 packages, each \(\frac{6}{5}\) kg. Total weight: \(8\times\frac{6}{5}=\frac{48}{5}=9\frac{3}{5}\) kg.

Step3: Analyze Option A

Keona's total is 10 kg, not \(\frac{9}{2}\) kg. So A is false.

Step4: Analyze Option B

Andre's total is \(9\frac{3}{5}\) kg. So B is true.

Step5: Analyze Option C

Andre's weight (\(9\frac{3}{5}\)) is less than Keona's (10), not 2 times more. So C is false.

Step6: Analyze Option D

Andre has more packages, but his total weight ( \(9\frac{3}{5}\)) is less than Keona's (10). So D is false.

Step7: Analyze Option E

Keona's total is 10 kg, Andre's is \(9\frac{3}{5}\) kg. 10 > \(9\frac{3}{5}\), so E is true.

Answer:

B. Andre’s packages of clay weigh \(9\frac{3}{5}\) kilograms in all.
E. Keona’s packages of clay weigh more than Andre’s packages of clay because 10 kilograms is greater than \(9\frac{3}{5}\) kilograms.