practice:
fill in the chart below with numbers of each subatomic particle. you may use the simulation
for elements up to neon. you may use a periodic table for any of the questions.

Question

Accepted Answer

# Explanation:
## Step1: Recall atomic structure concepts
- The mass number is written as a superscript before the element symbol.
- The atomic number is the number of protons and for a neutral atom, the number of electrons equals the number of protons.
- Number of neutrons = Mass number - Atomic number.
- For ions, the number of electrons changes: for an anion ($X^{n -}$), number of electrons=atomic number + n; for a cation ($X^{n+}$), number of electrons = atomic number - n.

## Step2: Analyze $^{7}\text{Li}$
- Mass number ($A$) = 7 (from $^{7}\text{Li}$).
- Atomic number ($Z$) of Li (from periodic table) = 3.
- Number of electrons (neutral atom) = 3.
- Number of protons = 3.
- Number of neutrons=$A - Z=7 - 3 = 4$.

## Step3: Analyze $^{4}\text{He}$
- Mass number ($A$) = 4 (from $^{4}\text{He}$).
- Atomic number ($Z$) of He (from periodic table) = 2.
- Number of electrons (neutral atom) = 2.
- Number of protons = 2.
- Number of neutrons=$A - Z=4 - 2 = 2$.

## Step4: Analyze the element with $e^{-}=6$, $p^{+}=6$, $n = 6$
- Symbol: $^{12}\text{C}$ (since $A=Z + n=6 + 6 = 12$, atomic number $Z = 6$ is for carbon).
- Mass number ($A$)=12.
- Atomic number ($Z$) = 6.

## Step5: Analyze the element with $e^{-}=6$, $p^{+}=6$, $n = 7$
- Symbol: $^{13}\text{C}$ (since $A=Z + n=6+7 = 13$, atomic number $Z = 6$ is for carbon).
- Mass number ($A$)=13.
- Atomic number ($Z$) = 6.

## Step6: Analyze $^{19}\text{F}^{-1}$
- Mass number ($A$) = 19 (from $^{19}\text{F}^{-1}$).
- Atomic number ($Z$) of F (from periodic table) = 9.
- Number of electrons: for $F^{-1}$, $e^{-}=Z + 1=9 + 1 = 10$.
- Number of protons = 9.
- Number of neutrons=$A - Z=19 - 9 = 10$.

## Step7: Analyze the element with $e^{-}=10$, $p^{+}=8$, $n = 8$
- Symbol: $^{16}\text{O}^{2 -}$ (since $A=Z + n=8 + 8 = 16$, atomic number $Z = 8$ is for oxygen. For $e^{-}=10$, $n_{e^{-}}=Z + 2$ so it is $O^{2-}$).
- Mass number ($A$)=16.
- Atomic number ($Z$) = 8.

## Step8: Analyze the element with $A = 9$, $Z = 4$, $e^{-}=2$
- Symbol: $^{9}\text{Be}^{2+}$ (since $n=A - Z=9 - 4 = 5$, and for $e^{-}=Z - 2$ (cation), atomic number $Z = 4$ is for beryllium).
- Number of protons = 4.
- Number of neutrons = 5.

# Answer:
| Symbol | Mass number | Atomic number | Number of electrons | Number of protons | Number of neutrons |
|---|---|---|---|---|---|
| $^{7}\text{Li}$ | 7 | 3 | 3 | 3 | 4 |
| $^{4}\text{He}$ | 4 | 2 | 2 | 2 | 2 |
| $^{12}\text{C}$ | 12 | 6 | 6 | 6 | 6 |
| $^{13}\text{C}$ | 13 | 6 | 6 | 6 | 7 |
| $^{19}\text{F}^{-1}$ | 19 | 9 | 10 | 9 | 10 |
| $^{16}\text{O}^{2 -}$ | 16 | 8 | 10 | 8 | 8 |
| $^{9}\text{Be}^{2+}$ | 9 | 4 | 2 | 4 | 5 |

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QUESTION IMAGE

Question

Explanation:

Step1: Recall atomic structure concepts

Step2: Analyze \(^{7}\text{Li}\)

Step3: Analyze \(^{4}\text{He}\)

Step4: Analyze the element with \(e^{-}=6\), \(p^{+}=6\), \(n = 6\)

Step5: Analyze the element with \(e^{-}=6\), \(p^{+}=6\), \(n = 7\)

Step6: Analyze \(^{19}\text{F}^{-1}\)

Step7: Analyze the element with \(e^{-}=10\), \(p^{+}=8\), \(n = 8\)

Step8: Analyze the element with \(A = 9\), \(Z = 4\), \(e^{-}=2\)

Answer:

Symbol	Mass number	Atomic number	Number of electrons	Number of protons	Number of neutrons
\(^{4}\text{He}\)	4	2	2	2	2
\(^{12}\text{C}\)	12	6	6	6	6
\(^{13}\text{C}\)	13	6	6	6	7
\(^{19}\text{F}^{-1}\)	19	9	10	9	10
\(^{16}\text{O}^{2 -}\)	16	8	10	8	8
\(^{9}\text{Be}^{2+}\)	9	4	2	4	5