Question

if ∠pqr measures 75°, what is the measure of ∠sqr? 97° 53° 45° 22°

Explanation:

Step1: Use the angle - addition formula

We know that \(\angle PQR=\angle PQS+\angle SQR\). Let \(\angle SQR = x\). Given \(\angle PQR = 75^{\circ}\) and \(\angle PQS=22^{\circ}\).

Step2: Solve for \(x\)

Substitute the values into the formula: \(75^{\circ}=22^{\circ}+x\). Then \(x = 75^{\circ}-22^{\circ}\).

$$x=53^{\circ}$$

Answer:

\(53^{\circ}\)