Question

in a population of sunflowers, the mean number of seeds is 1400, with a standard deviation of 350 seeds. what is the z - score of a sunflower which has 700 seeds? use the formula ( z=\frac{x-mu}{sigma} ).
( z = square )

Explanation:

Step1: Identify given values

We know that the mean \(\mu = 1400\), the standard deviation \(\sigma = 350\), and the value of \(x = 700\).

Step2: Substitute into z - score formula

The formula for the z - score is \(z=\frac{x - \mu}{\sigma}\). Substitute \(x = 700\), \(\mu = 1400\), and \(\sigma = 350\) into the formula:
\(z=\frac{700 - 1400}{350}\)
First, calculate the numerator: \(700-1400=- 700\)
Then, divide by the denominator: \(\frac{-700}{350}=-2\)

Answer:

\(-2\)