Question

polly and her friends were talking about how many road trips they had each been on.
road trips
name number
polly 6
manny 3
mona 12
scott 6
complete the picture graph.
road trips
polly
manny
mona
scott
= 3 road trips

Explanation:

Step1: Determine the number of cars for Polly

Polly has 6 road trips. Since each car represents 3 road trips, we calculate the number of cars as $6 \div 3 = 2$. Wait, no, wait. Wait the initial graph for Polly has some cars, but maybe I misread. Wait the key is 1 red car = 3 road trips. So for each person:

Polly: 6 road trips. Number of cars: $6 \div 3 = 2$? Wait no, maybe the initial cars are placeholders, and we need to color or mark the correct number. Wait, let's re-express:

For each person, number of road trips divided by 3 (since 1 car = 3 trips) gives the number of cars to represent.

Step2: Manny's cars

Manny has 3 road trips. $3 \div 3 = 1$ car.

Step3: Mona's cars

Mona has 12 road trips. $12 \div 3 = 4$ cars.

Step4: Scott's cars

Scott has 6 road trips. $6 \div 3 = 2$ cars.

Now, looking at the picture graph:

• Polly: needs 2 cars (since 6/3=2). Wait the initial Polly row has 9 cars? No, maybe the image is a bit unclear, but the key is each red car is 3 trips. So:

Polly: 6 trips → 6/3 = 2 cars (so color 2 cars)

Manny: 3 trips → 3/3 = 1 car (color 1 car)

Mona: 12 trips → 12/3 = 4 cars (color 4 cars)

Scott: 6 trips → 6/3 = 2 cars (color 2 cars)

Answer:

To complete the picture graph:

• Polly: Color 2 cars (since \( \frac{6}{3} = 2 \)).
• Manny: Color 1 car (since \( \frac{3}{3} = 1 \)).
• Mona: Color 4 cars (since \( \frac{12}{3} = 4 \)).
• Scott: Color 2 cars (since \( \frac{6}{3} = 2 \)).

(Note: The actual action is to mark the correct number of cars for each person based on the division by 3, as each car represents 3 road trips.)