Question

1. points d, e, and f are collinear, and e is between d and f. if df=22 cm and de=15 cm, what is the length of ef?

a) 7 cm
b) 37 cm
c) 1.47 cm
d) 11 cm

○ a) 7 cm
○ b) 37 cm
○ c) 1.47 cm
○ d) 11 cm

Explanation:

Step1: Recall segment addition postulate

Since E is between D and F, we have \( DF = DE + EF \).

Step2: Solve for EF

We know \( DF = 22 \) cm and \( DE = 15 \) cm. Rearranging the formula gives \( EF = DF - DE \). Substituting the values, we get \( EF = 22 - 15 = 7 \) cm.

Answer:

A) 7 cm