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Question
the point t(1, -6) is reflected over the y-axis. what are the coordinates of the resulting point, t?
Step1: Recall reflection over y - axis rule
When a point \((x,y)\) is reflected over the \(y\) - axis, the rule for the reflection is \((x,y)\to(-x,y)\).
Step2: Apply the rule to point \(T(1, - 6)\)
For the point \(T(1,-6)\), where \(x = 1\) and \(y=-6\), applying the reflection rule over the \(y\) - axis, we substitute \(x\) with \(-x\). So \(x = 1\) becomes \(-x=-1\) and \(y\) remains \(-6\).
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The coordinates of the resulting point \(T'\) are \((-1,-6)\)