Question

the point ( a(-2,0) ) reflected across the ( y )-axis.

Explanation:

Step1: Recall the reflection rule

When a point \((x,y)\) is reflected across the \(y -\)axis, the rule is \((x,y)\to(-x,y)\).

Step2: Apply the rule to the given point

For the point \(A(-2,0)\), here \(x = - 2\) and \(y=0\). Using the rule \((x,y)\to(-x,y)\), we substitute \(x=-2\) into \(-x\). So \(-x=-(-2) = 2\) and \(y = 0\) remains the same.

Answer:

The reflected point \(A'\) is \((2,0)\). But since \((2,0)\) is not among the given options, there might be a mistake in the problem setup (if we assume the options are from a mis - presented set, perhaps a typo in \(y\) - value, but based on the reflection rule for \(y\) - axis \((x,y)\to(-x,y)\) for \(A(-2,0)\) the correct reflection is \((2,0)\))