Question

4 place an x in the table to show whether the solution to each expression is a positive or negative value.
$4\frac{2}{3} \times \left(-5\frac{3}{7}\
ight) \div 1.86$
$\left(-\frac{3}{8}\
ight) \times \left(-7\frac{2}{5}\
ight) \times (-9)$
$(-3.54) \div \frac{1}{2} \div (-5.79)$
evaluate each expression
5 $\left(\frac{2}{3}\
ight) \left(\frac{12}{5}\
ight) (-1) \left(-\frac{7}{8}\
ight) = $
6 $-36.12 + \left(-5\frac{3}{5}\
ight) = $

Explanation:

Step1: Multiply the fractions and the integer

First, multiply the numerators and denominators of the fractions, and also multiply with the integer \(-1\). So we have \(\frac{2\times12\times(-1)\times(-7)}{3\times5\times1\times8}\).

Step2: Simplify the numerator and denominator

Calculate the numerator: \(2\times12 = 24\), \(24\times(-1)= -24\), \(-24\times(-7)=168\).
Calculate the denominator: \(3\times5 = 15\), \(15\times1 = 15\), \(15\times8 = 120\).
So the fraction becomes \(\frac{168}{120}\).

Step3: Simplify the fraction

Divide both the numerator and the denominator by their greatest common divisor, which is 24. \(\frac{168\div24}{120\div24}=\frac{7}{5}\).

Answer:

\(\frac{7}{5}\) (or \(1.4\))