Question

a pharmacy technician receives a prescription for insulin with instructions to inject 45 units daily for 28 days. the pharmacy stocks 10-ml vials that have a concentration of 300 units/ml. how many vials should the technician plan to dispense?
○ three
○ two
○ one
○ four

question 34
1 point
a pharmacy technician is preparing 1 l of 3% nacl solution.
how many g of nacl should the technician use?
○ 16 g
○ 40 g
○ 8 g

Explanation:

First Sub - Question (Insulin Vials)

Step 1: Calculate total units needed

The patient needs 45 units per day for 28 days. So total units \(= 45\times28\)
\(45\times28 = 1260\) units.

Step 2: Calculate units per vial

Each vial is 10 mL with a concentration of 300 units/mL. So units per vial \(= 10\times300\)
\(10\times300=3000\) units. Wait, no, wait. Wait, 10 mL vial, 300 units per mL. So units per vial is \(10\times300 = 3000\) units? But that can't be right. Wait, no, maybe I messed up. Wait, 45 units per day for 28 days: \(45\times28 = 1260\) units. Each vial is 10 mL, 300 units/mL. So volume needed per day: \(45\) units \(\div300\) units/mL \(= 0.15\) mL per day. For 28 days: \(0.15\times28 = 4.2\) mL. Each vial is 10 mL. So number of vials: \(4.2\div10 = 0.42\)? No, that's wrong. Wait, no, total units: 45 28 = 1260 units. Each vial has 300 units/mL 10 mL = 3000 units. Wait, 1260 units is less than 3000 units? But that would be one vial. But maybe I made a mistake. Wait, no, 45 units per day, 28 days: 4528 = 1260 units. Each vial is 10 mL, 300 units per mL: 10300 = 3000 units. So 1260 < 3000, so one vial? But the options have one as an option. Wait, maybe my calculation is wrong. Wait, 45 units per day, 28 days: 4528 = 1260 units. Each vial: 10 mL 300 units/mL = 3000 units. So 1260 units is less than 3000 units, so one vial.

Wait, maybe I messed up the concentration. Wait, 300 units per mL, 10 mL vial: 30010 = 3000 units. Total needed: 4528 = 1260 units. So 1 vial is enough. So the answer is One.

Step 3: Wait, but let's re - check. 45 units per day, 28 days: 4528 = 1260 units. Each vial has 300 units/mL 10 mL = 3000 units. So 1260 ≤ 3000, so one vial.

Step 1: Understand the percentage concentration

A 3% NaCl solution means 3 grams of NaCl per 100 mL of solution (by mass/volume, assuming the density of the solution is approximately 1 g/mL, so 100 mL of solution has a mass of approximately 100 g, and 3% of that is NaCl).

Step 2: Convert liters to milliliters

We need to prepare 1 L of solution. Since 1 L = 1000 mL.

Step 3: Calculate the mass of NaCl

For a 3% solution, the mass of NaCl \(=\frac{3\ g}{100\ mL}\times1000\ mL\)
\(\frac{3\times1000}{100}=30\ g\). Wait, but the options are 16 g, 40 g, 8 g. Wait, maybe the question has a typo or I misinterpret. Wait, maybe it's 0.9% normal saline, but no, the question says 3% NaCl. Wait, 1 L = 1000 mL. 3% of 1000 mL (assuming density 1 g/mL, so 1000 g of solution) is 30 g. But the options don't have 30 g. Wait, maybe the question is about 0.9%? No, the question says 3%. Wait, maybe the options are wrong, or I made a mistake. Wait, maybe the question is in a different context. Wait, maybe the solution is 3% by mass, and the density of the solution is 1 g/mL. So 1 L = 1000 mL = 1000 g. 3% of 1000 g is 30 g. But since 30 g is not an option, maybe there's a mistake. But assuming the question has a typo, or maybe I misread. Wait, the options are 16 g, 40 g, 8 g. Wait, maybe it's 0.8%? No. Wait, maybe the question is 1 L of 0.9% NaCl, but no. Alternatively, maybe the question is about 3% w/v, and the answer is 30 g, but since it's not an option, maybe the original question has a mistake. But if we assume that maybe the question is 1 L of 0.8% NaCl, but no. Alternatively, maybe I made a mistake. Wait, 3% NaCl solution: mass of NaCl = (3/100)volume of solution (in mL). Volume is 1000 mL. So (3/100)1000 = 30 g. Since 30 g is not an option, maybe the question is incorrect. But if we have to choose from the given options, maybe there's a mistake. But perhaps the intended question was 0.9% NaCl, but no. Alternatively, maybe the question is 1 L of 3% NaCl, and the options are wrong. But since the user provided the options, maybe I misread. Wait, the options are 16 g, 40 g, 8 g. Wait, maybe the question is 1 L of 0.8% NaCl? No. Alternatively, maybe the question is about 3% of 500 mL? No. Alternatively, maybe the question is in a different unit. Wait, maybe the density is different. But usually, for aqueous solutions, we assume density ≈1 g/mL. So I think there might be a mistake in the question or options. But if we proceed with the calculation, the correct answer should be 30 g, but since it's not an option, maybe the user made a typo.

Answer:

One

Second Sub - Question (NaCl Solution)