Question

the perimeter of the triangle below is 52 units. find the length of side \\( \overline { w x } \\).
write your answer without variables.
\\( w x = \square \\)

Explanation:

Step1: Set up the perimeter equation

The perimeter of a triangle is the sum of its sides. So, \((z - 1)+(4z + 3)+5z=52\).

Step2: Simplify the left - hand side of the equation

Combine like terms: \((z+4z + 5z)+(-1 + 3)=52\), which gives \(10z+2 = 52\).

Step3: Solve for \(z\)

Subtract 2 from both sides: \(10z=52 - 2=50\). Then divide both sides by 10: \(z=\frac{50}{10}=5\).

Step4: Find the length of \(WX\)

Since \(WX=z - 1\), substitute \(z = 5\) into the expression. So, \(WX=5-1\).

Answer:

\(4\)