Question

part f: use the periodic table to answer the following questions.
name\tsymbol\tatomic #\tatomic mass\tmass #\tp\tn\te⁻
iron\tfe\t26\t56\t\t26\t\t
oxygen\to\t8\t15.9994\t\t8\t\t
\tbr\t\t\t\t\t\t
\t\t27\t\t\t\t\t
mercury\t\t\t\t\t\t
\t\t\t\t11\t\t6\t\t
\txe\t\t\t\t\t\t
chlorine\t\t\t\t\t\t
\t\t\t\t\t12\t\t12

Explanation:

Step1: Recall Atomic Structure Rules

In an atom, \( \text{Atomic Number (Z)} = \text{Number of Protons (P)} = \text{Number of Electrons (e}^- \text{)} \), and \( \text{Mass Number (A)} = \text{Number of Protons (P)} + \text{Number of Neutrons (N)} \). Atomic Mass is approximately equal to Mass Number for most elements (or we can round Atomic Mass to get Mass Number).

Step2: Analyze Iron (Fe)

• Atomic Number (\( Z \)) = 26, so \( P = 26 \), \( e^- = 26 \).
• Atomic Mass ≈ 56 (Mass Number, \( A \)). Then \( N = A - P = 56 - 26 = 30 \).
• Mass Number (\( A \)) = 56.

Step3: Analyze Oxygen (O)

• Atomic Number (\( Z \)) = 8, so \( P = 8 \), \( e^- = 8 \).
• Atomic Mass = 15.9994 ≈ 16 (Mass Number, \( A \)). Then \( N = A - P = 16 - 8 = 8 \).
• Mass Number (\( A \)) = 16.

Step4: Analyze Bromine (Br)

• Symbol: Br. Atomic Number (\( Z \)) for Br is 35 (from periodic table). So \( P = 35 \), \( e^- = 35 \).
• Atomic Mass of Br is approximately 80 (or 79.904, round to 80). Then \( N = 80 - 35 = 45 \).
• Mass Number (\( A \)) = 80.

Step5: Analyze Element with Atomic Number 27

• Atomic Number 27: Element is Cobalt (Co). \( P = 27 \), \( e^- = 27 \).
• Atomic Mass of Co is approximately 59. So \( N = 59 - 27 = 32 \).
• Mass Number (\( A \)) = 59. Name: Cobalt.

Step6: Analyze Mercury (Hg)

• Symbol: Hg. Atomic Number (\( Z \)) for Hg is 80. So \( P = 80 \), \( e^- = 80 \).
• Atomic Mass of Hg is approximately 201 (or 200.59). Round to 201. Then \( N = 201 - 80 = 121 \).
• Mass Number (\( A \)) = 201.

Step7: Analyze Element with Mass Number 11 and Neutrons 6

• \( N = 6 \), \( A = 11 \). So \( P = A - N = 11 - 6 = 5 \). Atomic Number \( Z = 5 \), element is Boron (B). \( e^- = 5 \).
• Name: Boron. Atomic Number (\( Z \)) = 5.

Step8: Analyze Xenon (Xe)

• Symbol: Xe. Atomic Number (\( Z \)) for Xe is 54. So \( P = 54 \), \( e^- = 54 \).
• Let's find Mass Number: \( A = P + N \), but \( N \) isn't given? Wait, maybe from periodic table, Atomic Mass of Xe is ~131. So \( A \approx 131 \), \( N = 131 - 54 = 77 \). Or if we use other info, but main: \( P = 54 \), \( e^- = 54 \), Atomic Number \( Z = 54 \).

Step9: Analyze Chlorine (Cl)

• Symbol: Cl. Atomic Number (\( Z \)) for Cl is 17. So \( P = 17 \), \( e^- = 17 \).
• Atomic Mass of Cl is approximately 35 (or 35.453, round to 35 or 36; common is 35). If \( A = 35 \), \( N = 35 - 17 = 18 \); if \( A = 36 \), \( N = 36 - 17 = 19 \) (depends on isotope, but most abundant is \( A = 35 \)).

Step10: Analyze Element with \( P = 12 \), \( e^- = 12 \)

• \( P = 12 \), so Atomic Number \( Z = 12 \), element is Magnesium (Mg). \( N =? \), \( A = P + N \), but \( e^- = 12 \). Atomic Mass of Mg is ~24, so \( N = 24 - 12 = 12 \). Mass Number (\( A \)) = 24. Name: Magnesium.

(Note: The table has some blanks, above is filling based on periodic table and atomic structure rules. If the question was to fill the table, the filled values as per steps.)

Answer:

Filled table (key values):

Name	Symbol	Atomic #	Atomic Mass	Mass #	P	N	e⁻
Oxygen	O	8	15.9994	16	8	8	8
Bromine	Br	35	~80	80	35	45	35
Cobalt	Co	27	~59	59	27	32	27
Mercury	Hg	80	~201	201	80	121	80
Boron	B	5	~11	11	5	6	5
Xenon	Xe	54	~131	131	54	77	54
Chlorine	Cl	17	~35	35	17	18	17
Magnesium	Mg	12	~24	24	12	12	12

(If specific blanks were to be filled, e.g., for Iron: Mass # = 56, N = 30, e⁻ = 26; Oxygen: Mass # = 16, N = 8, e⁻ = 8; etc. Adjust based on exact question, but above is the analysis.)