Question

part a
an iron chloride compound contains 55.85 grams of iron and 106.5 grams of chlorine. what is the most likely empirical formula for this compound?
\bigcirc fe_3cl
\bigcirc fecl
\bigcirc fe_2cl
\bigcirc fecl_2
\bigcirc fecl_3

Explanation:

Step1: Calculate moles of Fe

Molar mass of Fe is 55.85 g/mol. Moles of Fe = $\frac{55.85\ g}{55.85\ g/mol}$ = 1 mol.

Step2: Calculate moles of Cl

Molar mass of Cl is 35.45 g/mol. Moles of Cl = $\frac{106.5\ g}{35.45\ g/mol}$ ≈ 3 mol.

Step3: Determine empirical formula

The mole ratio of Fe to Cl is 1:3, so the empirical formula is $FeCl_3$.

Answer:

$\boldsymbol{FeCl_3}$ (corresponding to the option "FeCl₃")