Question

part 2 calculations with the mole (points listed on each question—33 points total)
consider the following balanced reaction and answer the questions: 2nabr + cl₂ → 2nacl + br₂

1. list all the stoichiometric ratios (also called molar ratios) for nabr? (3 pts)

nabr/cl₂
nabr/nacl
nabr/br₂

Explanation:

Step1: Identify the stoichiometric coefficients

In the balanced chemical equation \(2NaBr + Cl_2
ightarrow2NaCl + Br_2\), the stoichiometric coefficients are \(2\) for \(NaBr\), \(1\) for \(Cl_2\), \(2\) for \(NaCl\), and \(1\) for \(Br_2\).

Step2: Calculate the stoichiometric ratios for \(NaBr\)

• For \(NaBr/Cl_2\): The ratio is \(\frac{2}{1}\) (coefficient of \(NaBr\) over coefficient of \(Cl_2\)).
• For \(NaBr/NaCl\): The ratio is \(\frac{2}{2}=1\) (coefficient of \(NaBr\) over coefficient of \(NaCl\)).
• For \(NaBr/Br_2\): The ratio is \(\frac{2}{1}\) (coefficient of \(NaBr\) over coefficient of \(Br_2\)).

Answer:

• \(NaBr/Cl_2\): \(\frac{2}{1}\)
• \(NaBr/NaCl\): \(1\)
• \(NaBr/Br_2\): \(\frac{2}{1}\)