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part 4 of 4 85.4 $\frac{kg}{m^{3}}$ to $\frac{g}{cm^{3}}$

Question

part 4 of 4
85.4 $\frac{kg}{m^{3}}$ to $\frac{g}{cm^{3}}$

Explanation:

Step1: Convert kilograms to grams

We know that $1\ kg = 1000\ g$, so $85.4\ kg=85.4\times1000 = 85400\ g$.

Step2: Convert cubic - meters to cubic - centimeters

We know that $1\ m = 100\ cm$, so $1\ m^{3}=(100\ cm)^{3}=1000000\ cm^{3}$.

Step3: Calculate the new density

The original density is $\frac{85.4\ kg}{1\ m^{3}}$, substituting the conversion values, we get $\frac{85400\ g}{1000000\ cm^{3}}=0.0854\ \frac{g}{cm^{3}}$.

Answer:

$0.0854$