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part a 1.28 mol carbon tetrafluoride m_cf₄ = g

Question

part a
1.28 mol carbon tetrafluoride
m_cf₄ = g

Explanation:

Step1: Calculate molar mass of CF₄

Molar mass = C + 4×F = 12.01 + 4×19.00 = 88.01 g/mol

Step2: Compute mass using n=m/M

m = n×M = 1.28 mol × 88.01 g/mol ≈ 112.65 g

Answer:

112.65