QUESTION IMAGE
Question
a pair of students obtained the following data:
- mass of sample: 8.64 g
- volume of water displaced: 3.2 ml
| material | density |
|---|---|
| concrete | 2.3 g/ml |
| wood (oak) | 0.60 g/ml |
| cork | 0.12 g/ml |
| aluminum | 2.7 g/ml |
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Step1: Recall density formula
Density is calculated as $
ho = \frac{m}{V}$, where $m$ is mass and $V$ is volume.
Step2: Substitute values
Given $m = 8.64\ \text{g}$ and $V = 3.2\ \text{mL}$, substitute into the formula: $
ho = \frac{8.64}{3.2}$.
Step3: Calculate density
$\frac{8.64}{3.2} = 2.7\ \text{g/mL}$.
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The material with density $2.7\ \text{g/mL}$ is aluminum, so the sample is aluminum.