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Question
- p4 + br2 → pbr3
Step1: Balance the phosphorus atoms
There are 4 phosphorus atoms in \(P_4\). So, we put a coefficient of 4 in front of \(PBr_3\) to balance the phosphorus atoms.
$$P_4+\text{__}Br_2
ightarrow4PBr_3$$
Step2: Balance the bromine atoms
In \(4PBr_3\), there are \(4\times3 = 12\) bromine atoms. Since each \(Br_2\) molecule has 2 bromine atoms, we need \(12\div2=6\) \(Br_2\) molecules.
$$P_4 + 6Br_2
ightarrow4PBr_3$$
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\(1\) \(P_4+6\) \(Br_2
ightarrow4\) \(PBr_3\)