QUESTION IMAGE
Question
one vertex of a polygon is located at (3, -2). after a rotation, the vertex is located at (2, 3). which transformations could have taken place? select two options. consider both clockwise and counterclockwise rotations when answering this question. ( r_{0,90^{circ}} ) ( r_{0,180^{circ}} ) ( r_{0,270^{circ}} ) ( r_{0,-90^{circ}} ) ( r_{0,-270^{circ}} )
Step1: Recall rotation rules
For a point \((x,y)\) rotated about the origin \((0,0)\):
- \(R_{0,90^{\circ}}\): \((x,y)\to(-y,x)\)
- \(R_{0,180^{\circ}}\): \((x,y)\to(-x,-y)\)
- \(R_{0,270^{\circ}}\): \((x,y)\to(y,-x)\)
- \(R_{0,- 90^{\circ}}\) (equivalent to \(R_{0,270^{\circ}}\)): \((x,y)\to(y,-x)\)
- \(R_{0,-270^{\circ}}\) (equivalent to \(R_{0,90^{\circ}}\)): \((x,y)\to(-y,x)\)
Step2: Apply rotation rules to the point \((3,-2)\)
- For \(R_{0,90^{\circ}}\): \((3,-2)\to(2,3)\) (since \(-y = 2\) and \(x = 3\))
- For \(R_{0,270^{\circ}}\): \((3,-2)\to(-2,-3)\)
- For \(R_{0,-90^{\circ}}\) (same as \(R_{0,270^{\circ}}\)): \((3,-2)\to(-2,-3)\)
- For \(R_{0,-270^{\circ}}\) (same as \(R_{0,90^{\circ}}\)): \((3,-2)\to(2,3)\)
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\(R_{0,90^{\circ}}\), \(R_{0,-270^{\circ}}\)