Question

one half of a balanced chemical equation is shown.
3mg(oh)₂ + 2h₃po₄
which lists the numbers of each atom the other half of the equation would contain?
○ 3 mg, 2 p, 14 o, 12 h
○ mg, 2 p, 14 o, 6 h
○ 3 mg, 8 p, 7 o, 6 h
○ 6 mg, 6 p, 2 o, 12 h

Explanation:

Step1: Calculate Mg atoms

In \(3\text{Mg(OH)}_2\), the coefficient of Mg is 3, so number of Mg atoms is 3.

Step2: Calculate P atoms

In \(2\text{H}_3\text{PO}_4\), the coefficient of P is 2, so number of P atoms is 2.

Step3: Calculate O atoms

For \(3\text{Mg(OH)}_2\): each \(\text{OH}_2\) has 2 O, so \(3\times2 = 6\) O. For \(2\text{H}_3\text{PO}_4\): each \(\text{H}_3\text{PO}_4\) has 4 O, so \(2\times4 = 8\). Total O: \(6 + 8 = 14\).

Step4: Calculate H atoms

For \(3\text{Mg(OH)}_2\): each \(\text{OH}_2\) has 2 H, so \(3\times2 = 6\) H. For \(2\text{H}_3\text{PO}_4\): each \(\text{H}_3\text{PO}_4\) has 3 H, so \(2\times3 = 6\). Total H: \(6 + 6 = 12\).

Answer:

3 Mg, 2 P, 14 O, 12 H (the first option)