Question

c₂h₅oh + 3o₂ → 2co₂ + 3h₂o + 1367 kj
what is the ratio between the energy and oxygen based on the equation?
fill in the green blank.

Explanation:

Step1: Analyze the balanced chemical equation

From the equation \(C_{2}H_{5}OH + 3O_{2}\to2CO_{2}+3H_{2}O + 1367\space kJ\), we can see that when \(3\space mol\) of \(O_{2}\) reacts, \(1367\space kJ\) of energy is released.

Step2: Calculate the ratio of energy to \(O_{2}\)

The ratio of energy (\(E\)) to moles of \(O_{2}(n)\) is \(\frac{E}{n}=\frac{1367\space kJ}{3\space mol}\approx455.7\space kJ/mol\)

Answer:

\(455.7\)