Question

oct 16, 2025 optg solving for missing side and angles using trig ratios
select the correct answer.
jefferson, bryan, marco
what is the value of x?
5
20\sqrt{3}
10\sqrt{2}
20

Explanation:

Step1: Use cosine ratio

In a right - triangle, \(\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}\). Here, \(\theta = 60^{\circ}\), adjacent side \(= 10\), and hypotenuse \(=x\). So, \(\cos60^{\circ}=\frac{10}{x}\).

Step2: Substitute the value of \(\cos60^{\circ}\)

Since \(\cos60^{\circ}=\frac{1}{2}\), we have \(\frac{1}{2}=\frac{10}{x}\).

Step3: Solve for \(x\)

Cross - multiply: \(x\times1 = 10\times2\).

Answer:

\(20\)