Question

an object is dropped from the top of a tower with a height of 1110 feet. neglecting air resistance, the height of the object at time t seconds is given by the polynomial -16t² + 1110. find the height of the object at t = 8 seconds.
the height of the object at 8 seconds is
square feet.

Explanation:

Step1: Identify the height formula

The height \( h(t) \) of the object at time \( t \) is given by \( h(t) = -16t^2 + 1110 \).

Step2: Substitute \( t = 8 \) into the formula

Substitute \( t = 8 \) into \( h(t) \):
\( h(8) = -16(8)^2 + 1110 \).

Step3: Calculate \( 8^2 \)

First, calculate \( 8^2 = 64 \).

Step4: Calculate \( -16 \times 64 \)

Then, \( -16 \times 64 = -1024 \).

Step5: Add 1110 to the result

Now, \( h(8) = -1024 + 1110 = 86 \).

Answer:

86