Question

an object has an acceleration of 18.0 m/s/s. if the net force acting upon this object were doubled, then its new acceleration would be ______ m/s/s.

Explanation:

Step1: Apply Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration. Initially, \(F_1=m\times a_1\), with \(a_1 = 18.0\space m/s^2\).

Step2: Analyze the case when force is doubled

When the net force is doubled (\(F_2 = 2F_1\)), since mass \(m\) remains constant (assuming the object's mass doesn't change), from \(F_2=m\times a_2\), substituting \(F_2 = 2F_1\) and \(F_1=m\times a_1\) gives \(2F_1=m\times a_2\). Then \(2\times(m\times a_1)=m\times a_2\). Canceling out the mass \(m\) (because \(m
eq0\)) from both sides of the equation, we get \(a_2 = 2a_1\).

Step3: Calculate the new acceleration

Substitute \(a_1 = 18.0\space m/s^2\) into \(a_2 = 2a_1\). So \(a_2=2\times18.0\space m/s^2=36.0\space m/s^2\).

Answer:

\(36.0\)