Question

the numbers of successes and the sample sizes for independent simple random samples from two populations are provided for a left - tailed test and an 80% confidence interval. complete parts (a) through (d)
$x_1 = 10,n_1 = 90,x_2 = 25,n_2 = 90,\alpha=0.10$
click here to view a table of areas under the standard normal curve for negative values of z.
click here to view a table of areas under the standard normal curve for positive values of z.

a. determine the sample proportions.
determine the sample proportion $\hat{p}_1$.
$\hat{p}_1=\square$(type an integer or a decimal. round to three decimal places as needed.)

Explanation:

Step1: Recall the formula for sample proportion

The formula for sample proportion is $\hat{p}=\frac{x}{n}$, where $x$ is the number of successes and $n$ is the sample size.

Step2: Substitute values for $\hat{p}_1$

Given $x_1 = 10$ and $n_1=90$, substitute into the formula: $\hat{p}_1=\frac{10}{90}$.

Step3: Calculate the value

$\frac{10}{90}=\frac{1}{9}\approx0.111$

Answer:

$0.111$