Question

number of washers,trial,time to travel 0.25 m t1(s),average,time to travel 0.50 m t2(s),average
1 washer mass = 4.9 g,trial #1,2.24,2.23,3.16,3.13
trial #2,2.21,3.08
trial #3,2.23,3.15
what is the average velocity of the car over the first 0.25m?
what is the average velocity of the car over the second 0.25m?

Explanation:

Step1: Recall average - velocity formula

The formula for average velocity is $v = \frac{\Delta x}{\Delta t}$, where $\Delta x$ is the displacement and $\Delta t$ is the time - interval.

Step2: Calculate average velocity for the first 0.25 m

Given $\Delta x_1=0.25$ m and the average time $t_1 = 2.23$ s. Using the formula $v_1=\frac{\Delta x_1}{t_1}$, we substitute the values: $v_1=\frac{0.25}{2.23}\approx0.11$ m/s.

Step3: Calculate average velocity for the second 0.25 m

The total distance for the second part is also $\Delta x_2 = 0.25$ m. The time for the second 0.25 m is $t_{2 - part}=t_2 - t_1$, where $t_2 = 3.13$ s and $t_1 = 2.23$ s. So $t_{2 - part}=3.13 - 2.23=0.9$ s. Using the formula $v_2=\frac{\Delta x_2}{t_{2 - part}}$, we substitute the values: $v_2=\frac{0.25}{0.9}\approx0.28$ m/s.

Answer:

The average velocity of the car over the first 0.25 m is approximately 0.11 m/s.
The average velocity of the car over the second 0.25 m is approximately 0.28 m/s.