Question

the number line below models the expression 341 + 448. enter numbers to label each jump: first by 100s, then by 10s, and then by 1 s. enter the sum of 341 and 448 at the end of the number line. 341 741 781

Explanation:

Step1: Analyze the first jump (100's)

The first jump is from 341 to 741. To find the length of this jump, calculate the difference: \(741 - 341 = 400\). So the first jump (by 100's) is 400.

Step2: Analyze the second jump (10's)

The second jump is from 741 to 781. Calculate the difference: \(781 - 741 = 40\). So the second jump (by 10's) is 40.

Step3: Analyze the third jump (1's)

The third jump is from 781 to the final sum. We know the total addition is 448, and we've already added 400 (first jump) and 40 (second jump), so the remaining addition for the 1's place is \(448 - 400 - 40 = 8\). So the third jump (by 1's) is 8.

Step4: Calculate the final sum

To find the sum of 341 and 448, we can also add the jumps: \(341 + 400 + 40 + 8 = 789\). Alternatively, \(341 + 448 = 789\).

Answer:

First jump (above 341 - 741): 400
Second jump (above 741 - 781): 40
Third jump (above 781 - end): 8
Final sum (end of number line): 789