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Question
newtons second law quick check
blake and drew are playing horseshoes. blake takes the first turn, and his horseshoe lands three - fourths of the way to the target. drew takes the next turn, and his horseshoe lands past the target. which statement best explains the results? (1 point)
the horseshoes have the same mass, but drew threw with less force than blake.
drew used a horseshoe with more mass and threw with less force than blake.
the horseshoes have the same mass, but drew threw with more force than blake.
drew used a horseshoe with more mass and threw with the same force as blake.
Step1: Recall Newton's Second Law
Newton's second law is \(F = ma\) (where \(F\) is force, \(m\) is mass, and \(a\) is acceleration). Assuming the horseshoes have the same mass (\(m\) is constant), a greater force (\(F\)) will lead to a greater acceleration (\(a\)). A greater acceleration means the horseshoe will travel a greater distance.
Step2: Analyze each option
- Option 1: If \(m\) is same and \(F_{Drew}
- Option 2: If \(m_{Drew}>m_{Blake}\) and \(F_{Drew}
- Option 3: If \(m\) is same and \(F_{Drew}>F_{Blake}\), then \(a_{Drew}>a_{Blake}\). A greater acceleration means the horseshoe (Drew's) will travel a greater distance (past the target as Blake's is three - fourths of the way).
- Option 4: If \(m_{Drew}>m_{Blake}\) and \(F_{Drew} = F_{Blake}\), using \(a=\frac{F}{m}\), \(a_{Drew}
- Option 2: If \(m_{Drew}>m_{Blake}\) and \(F_{Drew}
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The horseshoes have the same mass, but Drew threw with more force than Blake.