Question

name date practic combining like terms which terms are like terms? (not all terms will be used.) circle all terms that draw a square around underline all terms draw an x through all can be combined with all terms that can be that can be combined terms that can be 3a. combined with 4b. with ( a^{2} ) combined with 5. 1. 14a 2. 5ab 3. 3b 4. ( 3a^{2} ) 5. ( 4b^{2} ) 6. 17 7. 100 8. 14ab 9. ( 5a^{3} ) 10. 4a 11. 16b 12. ( 73a^{2} ) simplify the following expressions by combining like terms. show all work on a separate sheet of paper and box your answer. 13. ( 4x - 6x ) 14. ( 7y + 5y - 5y ) 15. ( 4r + 4y - 8 ) 16. ( 3m + 4n - 6n ) 17. ( 4g + 6g - 3g ) 18. ( 15t - 5 + 2t ) 19. ( 13x - 7y + 4x ) 20. ( 5x^{2}-4x + 9x^{2} ) 21. ( 4b + 7a - 8 ) 22. ( 13r + 5s - 2r ) 23. ( a + a + 3b + b ) 24. ( 3y - 4y^{2}+3y ) 25. ( (3a - b)+2a ) 26. ( 2w + 4w^{2}-5w^{2} ) 27. ( c^{3}+4c - 4c^{3} ) 28. ( a - 3b + 5c + 4a ) 29. ( 2x + 7x - 6x + 8 ) 30. ( 11q + 5p - 8q + 7p ) 31. ( 3mn + 4m - 2mn ) 32. ( 0t - 9t + 6u + 4u^{4} ) 33. ( 11d + 5t - 21d + 5 - 8 ) 34. ( 12 + 9x - 6x - 19 ) 35. ( y^{2}+3y^{2}-6y + 4y^{2} ) 36. ( 2 - 5t + 8 + 5t - 8 ) when part of an expression is over or under a division bar, you must act as if that part of the expression is inside of parentheses. use pemdas to decide if you can simplify the expression any further. (think: did you get a fraction that you can simplify?) 37. ( \frac{14r + 12s}{4s - 10s} ) 38. ( \frac{3x^{2}}{12 - 14x^{2}} ) 39. ( \frac{2 - 5t}{2 + 5t - 4t} ) 40. ( \frac{2x - 6y + 4x}{3y - 8 + y} ) 41. ( \frac{11d + 9d}{8d - 3d} ) 42. ( \frac{12x - 7x}{5x} ) bonus: simplify the expression below by combining like terms. ( 4z + x - 5x + 7y - 3x + 5y^{2}-3z + 16z + 14x - 5 )

Explanation:

Step1: Combine like - terms for \(4z + x-5x + 7y-3x + 5y^{2}-3z + 16z+14x - 5\)

Group the \(z\) - terms: \((4z-3z + 16z)\)
Group the \(x\) - terms: \((x-5x-3x + 14x)\)
Group the \(y\) - terms: \(7y\)
The constant term: \(-5\)
The \(y^{2}\) - term: \(5y^{2}\)

Step2: Calculate each group

For \(z\) - terms: \(4z-3z + 16z=(4 - 3+16)z = 17z\)
For \(x\) - terms: \(x-5x-3x + 14x=(1-5 - 3 + 14)x=7x\)
The \(y\) - term remains \(7y\)
The \(y^{2}\) - term remains \(5y^{2}\)
The constant term remains \(-5\)

Answer:

\(17z+7x + 7y+5y^{2}-5\)