Question

name:
date:
nomenclature #1 simple ionic

1. na₃n
2. sns
3. caf₂
4. li₂o
5. cs₃n
6. sro
7. k₃p
8. naf
9. sn₃p₄
10. li₃p
11. bal₂
12. csbr
13. ca₃n₂
14. sno
15. al₂o₃
16. libr
17. bal₂
18. csf
19. ain
20. kbr

Explanation:

Step1: Naming ionic compounds

For ionic compounds, the name of the cation (metal) is written first, followed by the name of the anion (non - metal). For metals that can have multiple charges (like Sn, Tin), we need to determine the charge based on the anion's charge and the formula.

• For \(Na_3N\): \(Na\) (sodium) is the cation. \(N^{3 -}\) (nitride) is the anion. So it is sodium nitride.
• For \(SnS\): \(S^{2 -}\) (sulfide). Let the charge of \(Sn\) be \(x\). Using the formula \(x+( - 2)=0\) (since the compound is neutral), \(x = + 2\). So it is tin (II) sulfide.
• For \(CaF_2\): \(Ca\) (calcium) is the cation. \(F^{-}\) (fluoride) is the anion. So it is calcium fluoride.
• For \(Li_2O\): \(Li\) (lithium) is the cation. \(O^{2 -}\) (oxide) is the anion. So it is lithium oxide.
• For \(Cs_3N\): \(Cs\) (cesium) is the cation. \(N^{3 -}\) (nitride) is the anion. So it is cesium nitride.
• For \(SrO\): \(Sr\) (strontium) is the cation. \(O^{2 -}\) (oxide) is the anion. So it is strontium oxide.
• For \(K_3P\): \(K\) (potassium) is the cation. \(P^{3 -}\) (phosphide) is the anion. So it is potassium phosphide.
• For \(NaF\): \(Na\) (sodium) is the cation. \(F^{-}\) (fluoride) is the anion. So it is sodium fluoride.
• For \(Sn_3P_4\): Let the charge of \(Sn\) be \(x\). \(P^{3 -}\). Using \(3x+4\times(- 3)=0\), \(3x = 12\), \(x = + 4\). So it is tin (IV) phosphide.
• For \(Li_3P\): \(Li\) (lithium) is the cation. \(P^{3 -}\) (phosphide) is the anion. So it is lithium phosphide.
• For \(BaI_2\): \(Ba\) (barium) is the cation. \(I^{-}\) (iodide) is the anion. So it is barium iodide.
• For \(CsBr\): \(Cs\) (cesium) is the cation. \(Br^{-}\) (bromide) is the anion. So it is cesium bromide.
• For \(Ca_3N_2\): \(Ca\) (calcium) is the cation. \(N^{3 -}\) (nitride) is the anion. So it is calcium nitride.
• For \(SnO\): \(O^{2 -}\) (oxide). Let the charge of \(Sn\) be \(x\). \(x+( - 2)=0\), \(x = + 2\). So it is tin (II) oxide.
• For \(Al_2O_3\): \(Al\) (aluminum) is the cation. \(O^{2 -}\) (oxide) is the anion. So it is aluminum oxide.
• For \(LiBr\): \(Li\) (lithium) is the cation. \(Br^{-}\) (bromide) is the anion. So it is lithium bromide.
• For \(BaI_2\): \(Ba\) (barium) is the cation. \(I^{-}\) (iodide) is the anion. So it is barium iodide.
• For \(CsF\): \(Cs\) (cesium) is the cation. \(F^{-}\) (fluoride) is the anion. So it is cesium fluoride.
• For \(AlN\): \(Al\) (aluminum) is the cation. \(N^{3 -}\) (nitride) is the anion. So it is aluminum nitride.
• For \(KBr\): \(K\) (potassium) is the cation. \(Br^{-}\) (bromide) is the anion. So it is potassium bromide.

Answer:

1. Sodium nitride
2. Tin (II) sulfide
3. Calcium fluoride
4. Lithium oxide
5. Cesium nitride
6. Strontium oxide
7. Potassium phosphide
8. Sodium fluoride
9. Tin (IV) phosphide
10. Lithium phosphide
11. Barium iodide
12. Cesium bromide
13. Calcium nitride
14. Tin (II) oxide
15. Aluminum oxide
16. Lithium bromide
17. Barium iodide
18. Cesium fluoride
19. Aluminum nitride
20. Potassium bromide