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Question
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find the slope between each pair of points. then, using the pythagorean theorem, find the distance between each pair of points. you may use the graph to help.
- $(-2, -3)(1, 1)$
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slope:
distance:
- $(-7, 5)(-2, -7)$
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slope:
distance:
Problem 17: Points \((-2, -3)\) and \((1, 1)\)
Slope Calculation
Step1: Recall slope formula
The slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by \(m = \frac{y_2 - y_1}{x_2 - x_1}\).
Here, \(x_1 = -2\), \(y_1 = -3\), \(x_2 = 1\), \(y_2 = 1\).
Step2: Substitute values into slope formula
\(m = \frac{1 - (-3)}{1 - (-2)} = \frac{1 + 3}{1 + 2} = \frac{4}{3}\)
Step1: Find horizontal and vertical distances
Horizontal distance (run) \(= |x_2 - x_1| = |1 - (-2)| = 3\)
Vertical distance (rise) \(= |y_2 - y_1| = |1 - (-3)| = 4\)
Step2: Apply Pythagorean theorem
Let \(d\) be the distance. Then \(d^2 = (\text{run})^2 + (\text{rise})^2\)
\(d^2 = 3^2 + 4^2 = 9 + 16 = 25\)
Step3: Take square root
\(d = \sqrt{25} = 5\)
Step1: Recall slope formula
The slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is \(m = \frac{y_2 - y_1}{x_2 - x_1}\).
Here, \(x_1 = -7\), \(y_1 = 5\), \(x_2 = -2\), \(y_2 = -7\).
Step2: Substitute values into slope formula
\(m = \frac{-7 - 5}{-2 - (-7)} = \frac{-12}{-2 + 7} = \frac{-12}{5} = -\frac{12}{5}\)
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(Slope): \(\frac{4}{3}\)