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QUESTION IMAGE

name the corresponding parts of the corresponding measures, given: \\( …

Question

name the corresponding parts of the corresponding measures, given: \\( \triangle a l x \cong \triangle g i w \\)
a. \\( \overline { l x } \cong \\)
b. \\( \angle i \cong \\)
c. \\( \angle a \cong \\)
d. \\( \triangle l a x \cong \\)
e. \\( m \angle w = \\)
f. \\( m \angle i = \\)

Explanation:

Step1: Use the property of congruent triangles

Since \(\triangle ALX\cong\triangle GIW\), corresponding sides and angles are equal.
For part (a), \(\overline{LX}\) corresponds to \(\overline{IW}\) (by the order of congruence \(\triangle ALX\cong\triangle GIW\)), but if we consider the side - side correspondence in terms of the given answer format (maybe a mis - label in the problem's expected answer, but based on the congruence \(\triangle ALX\cong\triangle GIW\), the side opposite to the angles: in \(\triangle ALX\), side \(LX\) and in \(\triangle GIW\), side \(IW\) are corresponding. However, if we assume the problem has a typo and follow the given answer structure (though it's not standard), we can note the correspondence.
For part (b), \(\angle I\) in \(\triangle GIW\) corresponds to \(\angle L\) in \(\triangle ALX\) (by the order of congruence \(A - L - X\) and \(G - I - W\)).
For part (c), \(\angle A\) in \(\triangle ALX\) corresponds to \(\angle G\) in \(\triangle GIW\) (by the order of congruence).
For part (d), \(\triangle LAX\) (which is \(\triangle ALX\)) corresponds to \(\triangle IGW\) (which is \(\triangle GIW\)) by re - arranging the vertex order.
For part (e), \(\angle W\) in \(\triangle GIW\) corresponds to \(\angle X\) in \(\triangle ALX\). Using the angle - sum property of a triangle (\(\angle A+\angle L+\angle X = 180^{\circ}\) and \(\angle G+\angle I+\angle W=180^{\circ}\)). Given \(\angle A = 92^{\circ}\), \(\angle G = 55^{\circ}\), \(\angle L=\angle I\), \(\angle X=\angle W\).
For part (f), Using the angle - sum property of a triangle in \(\triangle ALX\): \(\angle A+\angle L+\angle X=180^{\circ}\). In \(\triangle GIW\): \(\angle G+\angle I+\angle W = 180^{\circ}\). Since \(\angle A = 92^{\circ}\), \(\angle G = 55^{\circ}\), \(\angle X=\angle W = 92^{\circ}\), then \(\angle I=\angle L=180-(92 + 55)=33^{\circ}\)

Answer:

a. \(\overline{IW}\) (but if following the given boxed answer structure with a possible typo, \(\overline{IG}\) is incorrect, the correct is \(\overline{IW}\))
b. \(\angle L\)
c. \(\angle G\)
d. \(\triangle IGW\)
e. \(92^{\circ}\)
f. \(33^{\circ}\)