Question

multiply.
$(8 \times 10^{-2})(5 \times 10^{-2})$
$4 \times 10^{-2}$ $4 \times 10^{-4}$ $4 \times 10^{4}$ $4 \times 10^{-3}$
submit

Explanation:

Step1: Multiply the coefficients

$8 \times 5 = 40$

Step2: Multiply the powers of 10

$10^{-2} \times 10^{-2} = 10^{-2 + (-2)} = 10^{-4}$

Step3: Combine and simplify

$40 \times 10^{-4} = 4 \times 10^{-3} \times 10^{-1} = 4 \times 10^{-4}$

Answer:

$4 \times 10^{-4}$