Question

multiply: $-c^2(3c - 2)$

1. apply the distributive property. $-c^2(3c) + (-c^2)(-2)$ $square c^3 + square c^2$
2. multiply.

Explanation:

Step1: Distribute the monomial

$-c^2(3c) + (-c^2)(-2)$

Step2: Multiply the first terms

$-c^2 \times 3c = -3c^{2+1} = -3c^3$

Step3: Multiply the second terms

$-c^2 \times (-2) = 2c^2$[LLM SSE On Failure]

Answer:

Step1: Distribute the monomial

$-c^2(3c) + (-c^2)(-2)$

Step2: Multiply the first terms

$-c^2 \times 3c = -3c^{2+1} = -3c^3$

Step3: Multiply the second terms

$-c^2 \times (-2) = 2c^2$[LLM SSE On Failure]