Question

5 multiple choice 5 points a bag contains 8 red marbles, 12 blue marbles, and 17 green marbles. if one marble is randomly selected from the bag, what is the probability that the marble is red or green? options: 8/17, 29/37, 30/37, 25/37 (with 25/37 selected) 6 multiple choice 5 points greg wrote the numbers 1 through 9 on pieces of paper and placed them in a hat. he will randomly select one piece of paper from the hat. he will not replace it. greg will then randomly select a second piece of paper from the hat. what is the probability that greg will select a piece of paper with an odd number on it and then select one with an even number on it? options: 9/17, 19/18, 20/81, 5/18 (with 9/17 selected)

Explanation:

Question 5

Step1: Find total marbles

Total marbles = 8 (red) + 12 (blue) + 17 (green) = 37.

Step2: Find red or green count

Red or green = 8 + 17 = 25.

Step3: Calculate probability

Probability = $\frac{25}{37}$.

Step1: Odd numbers (1 - 9)

Odd numbers: 1, 3, 5, 7, 9 → 5 numbers. Total = 9. Probability of odd first: $\frac{5}{9}$.

Step2: Even numbers after odd (no replacement)

After removing one odd, total = 8. Even numbers: 2, 4, 6, 8 → 4 numbers. Probability of even second: $\frac{4}{8}=\frac{1}{2}$.

Step3: Multiply probabilities

Combined probability = $\frac{5}{9} \times \frac{1}{2} = \frac{5}{18}$.

Answer:

$\frac{25}{37}$ (the option with $\frac{25}{37}$)

Question 6